W88 on Melbourne
475 kt thermonuclear weapon · Australia · Population 5,078,000 · Density 2,500/km²
About this scenario
This page calculates what would happen if the W88 (USA, 1988) detonated over Melbourne (Australia). Modern SLBM warhead.
The second-largest city in Australia and capital of the state of Victoria. With an urban-core density of about 2,500 people per km², even a relatively small detonation over the city center would affect a large population.
The W88 delivers 475 kt of explosive yield — 32× more powerful than the Hiroshima bomb. The tables below show calculated effect radii for an air burst (optimized for blast spread) and a surface burst (which produces massive fallout).
Air-burst effects (W88 over Melbourne)
| Effect zone | Radius | Est. affected |
|---|---|---|
| Fireball (vaporization, 100% fatal) | 1.71 km | ~22,866 |
| Severe blast (20 PSI, ~98% fatal) | 3.68 km | ~81,613 |
| Moderate blast (5 PSI, ~50% fatal) | 7.87 km | ~190,113 |
| Light blast (1 PSI, glass injuries) | 22.40 km | ~172,634 |
| 3rd-degree thermal burns | 8.39 km | — |
| 2nd-degree thermal burns | 15.02 km | — |
Estimated total fatalities: ~294,592 · Estimated total affected (inside 1 PSI light-blast radius): ~3,939,516.
Surface-burst effects (with fallout)
A surface burst trades blast spread for radioactive fallout — much smaller blast radii but a large lethal fallout plume drifting downwind. This is what would happen if the W88 struck ground level rather than detonating optimally above Melbourne.
| Effect zone | Radius (surface burst) |
|---|---|
| Fireball | 1.37 km |
| Severe blast (20 PSI) | 2.03 km |
| Moderate blast (5 PSI) | 4.33 km |
| Light blast (1 PSI) | 12.32 km |
| 3rd-degree thermal burns | 5.03 km |
| Lethal fallout zone | ~141.2 km |
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See the actual blast zones overlaid on a map of Melbourne with population-density-based casualty estimates updated in real time as you move the detonation point.
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Other weapons on Melbourne
FAQ
What would happen if the W88 detonated over Melbourne?
In an air burst over Melbourne, the W88 (475 kt) would produce a fireball about 1.71 km in radius. The 5 PSI moderate-blast zone — where most residential buildings collapse — would extend to 7.87 km. Light blast damage and shattered windows would reach 22.40 km. Given Melbourne's urban density (~2,500/km²), this scenario yields an estimated 294,592 immediate fatalities and about 172,634 additional injured.
How many people would die in Melbourne from a W88 strike?
An air burst of the W88 over Melbourne could cause an estimated 294,592 immediate fatalities and 172,634 additional injuries. The fireball alone (radius 1.71 km) would kill approximately 22,866 people; the severe-blast zone (20 PSI, radius 3.68 km) would add 81,613; the moderate-blast zone (5 PSI, radius 7.87 km) would add 190,113 more. Real numbers depend heavily on time of day, sheltering, weather, and altitude of detonation.
What is the blast radius of the W88 on Melbourne?
For an air burst over Melbourne: fireball 1.71 km, severe blast (20 PSI) 3.68 km, moderate blast (5 PSI) 7.87 km, light blast (1 PSI) 22.40 km. Thermal radiation causes 3rd-degree burns out to 8.39 km. A surface burst would shrink the blast radii by roughly 40 percent but generate massive radioactive fallout extending ~141 km from ground zero.
Is the W88 bigger than the bomb that hit Hiroshima?
The Hiroshima bomb (Little Boy) had a yield of about 15 kilotons. The W88 at 475 kt is 32× more powerful than the Hiroshima bomb.