B83 on Los Angeles

1.2 Mt thermonuclear weapon · USA · Population 3,898,747 · Density 3,200/km²

About this scenario

This page calculates what would happen if the B83 (USA, 1983) detonated over Los Angeles (USA). Most powerful US weapon in active service.

The second-most populous US city, sprawling across Southern California with a metro area of nearly 13 million. With an urban-core density of about 3,200 people per km², even a relatively small detonation over the city center would affect a large population.

The B83 delivers 1.2 Mt of explosive yield — 80× more powerful than the Hiroshima bomb. The tables below show calculated effect radii for an air burst (optimized for blast spread) and a surface burst (which produces massive fallout).

Air-burst effects (B83 over Los Angeles)

Effect zoneRadiusEst. affected
Fireball (vaporization, 100% fatal)2.47 km~61,430
Severe blast (20 PSI, ~98% fatal)5.00 km~185,106
Moderate blast (5 PSI, ~50% fatal)10.69 km~448,603
Light blast (1 PSI, glass injuries)30.41 km~407,360
3rd-degree thermal burns12.26 km
2nd-degree thermal burns21.96 km

Estimated total fatalities: ~695,139 · Estimated total affected (inside 1 PSI light-blast radius): ~9,295,970.

Surface-burst effects (with fallout)

A surface burst trades blast spread for radioactive fallout — much smaller blast radii but a large lethal fallout plume drifting downwind. This is what would happen if the B83 struck ground level rather than detonating optimally above Los Angeles.

Effect zoneRadius (surface burst)
Fireball1.98 km
Severe blast (20 PSI)2.75 km
Moderate blast (5 PSI)5.88 km
Light blast (1 PSI)16.72 km
3rd-degree thermal burns7.36 km
Lethal fallout zone~204.6 km

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See the actual blast zones overlaid on a map of Los Angeles with population-density-based casualty estimates updated in real time as you move the detonation point.

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B83 on other cities

Other weapons on Los Angeles

FAQ

What would happen if the B83 detonated over Los Angeles?

In an air burst over Los Angeles, the B83 (1.2 Mt) would produce a fireball about 2.47 km in radius. The 5 PSI moderate-blast zone — where most residential buildings collapse — would extend to 10.69 km. Light blast damage and shattered windows would reach 30.41 km. Given Los Angeles's urban density (~3,200/km²), this scenario yields an estimated 695,139 immediate fatalities and about 407,360 additional injured.

How many people would die in Los Angeles from a B83 strike?

An air burst of the B83 over Los Angeles could cause an estimated 695,139 immediate fatalities and 407,360 additional injuries. The fireball alone (radius 2.47 km) would kill approximately 61,430 people; the severe-blast zone (20 PSI, radius 5.00 km) would add 185,106; the moderate-blast zone (5 PSI, radius 10.69 km) would add 448,603 more. Real numbers depend heavily on time of day, sheltering, weather, and altitude of detonation.

What is the blast radius of the B83 on Los Angeles?

For an air burst over Los Angeles: fireball 2.47 km, severe blast (20 PSI) 5.00 km, moderate blast (5 PSI) 10.69 km, light blast (1 PSI) 30.41 km. Thermal radiation causes 3rd-degree burns out to 12.26 km. A surface burst would shrink the blast radii by roughly 40 percent but generate massive radioactive fallout extending ~205 km from ground zero.

Is the B83 bigger than the bomb that hit Hiroshima?

The Hiroshima bomb (Little Boy) had a yield of about 15 kilotons. The B83 at 1.2 Mt is 80× more powerful than the Hiroshima bomb.

Casualty math uses Los Angeles's urban-core density and the scaling laws on the methodology page. See B83 weapon details, the Los Angeles scenario overview, or browse all scenarios.