B83 on Moscow

1.2 Mt thermonuclear weapon · Russia · Population 12,600,000 · Density 4,900/km²

About this scenario

This page calculates what would happen if the B83 (USA, 1983) detonated over Moscow (Russia). Most powerful US weapon in active service.

The capital of Russia and the largest city in Europe by population. With an urban-core density of about 4,900 people per km², even a relatively small detonation over the city center would affect a large population.

The B83 delivers 1.2 Mt of explosive yield — 80× more powerful than the Hiroshima bomb. The tables below show calculated effect radii for an air burst (optimized for blast spread) and a surface burst (which produces massive fallout).

Air-burst effects (B83 over Moscow)

Effect zoneRadiusEst. affected
Fireball (vaporization, 100% fatal)2.47 km~94,065
Severe blast (20 PSI, ~98% fatal)5.00 km~283,443
Moderate blast (5 PSI, ~50% fatal)10.69 km~686,923
Light blast (1 PSI, glass injuries)30.41 km~623,770
3rd-degree thermal burns12.26 km
2nd-degree thermal burns21.96 km

Estimated total fatalities: ~1,064,431 · Estimated total affected (inside 1 PSI light-blast radius): ~14,234,454.

Surface-burst effects (with fallout)

A surface burst trades blast spread for radioactive fallout — much smaller blast radii but a large lethal fallout plume drifting downwind. This is what would happen if the B83 struck ground level rather than detonating optimally above Moscow.

Effect zoneRadius (surface burst)
Fireball1.98 km
Severe blast (20 PSI)2.75 km
Moderate blast (5 PSI)5.88 km
Light blast (1 PSI)16.72 km
3rd-degree thermal burns7.36 km
Lethal fallout zone~204.6 km

Run this scenario in the simulator

See the actual blast zones overlaid on a map of Moscow with population-density-based casualty estimates updated in real time as you move the detonation point.

🎯 Open this scenario on the map

B83 on other cities

Other weapons on Moscow

FAQ

What would happen if the B83 detonated over Moscow?

In an air burst over Moscow, the B83 (1.2 Mt) would produce a fireball about 2.47 km in radius. The 5 PSI moderate-blast zone — where most residential buildings collapse — would extend to 10.69 km. Light blast damage and shattered windows would reach 30.41 km. Given Moscow's urban density (~4,900/km²), this scenario yields an estimated 1,064,431 immediate fatalities and about 623,770 additional injured.

How many people would die in Moscow from a B83 strike?

An air burst of the B83 over Moscow could cause an estimated 1,064,431 immediate fatalities and 623,770 additional injuries. The fireball alone (radius 2.47 km) would kill approximately 94,065 people; the severe-blast zone (20 PSI, radius 5.00 km) would add 283,443; the moderate-blast zone (5 PSI, radius 10.69 km) would add 686,923 more. Real numbers depend heavily on time of day, sheltering, weather, and altitude of detonation.

What is the blast radius of the B83 on Moscow?

For an air burst over Moscow: fireball 2.47 km, severe blast (20 PSI) 5.00 km, moderate blast (5 PSI) 10.69 km, light blast (1 PSI) 30.41 km. Thermal radiation causes 3rd-degree burns out to 12.26 km. A surface burst would shrink the blast radii by roughly 40 percent but generate massive radioactive fallout extending ~205 km from ground zero.

Is the B83 bigger than the bomb that hit Hiroshima?

The Hiroshima bomb (Little Boy) had a yield of about 15 kilotons. The B83 at 1.2 Mt is 80× more powerful than the Hiroshima bomb.

Casualty math uses Moscow's urban-core density and the scaling laws on the methodology page. See B83 weapon details, the Moscow scenario overview, or browse all scenarios.